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JEE Mains · Physics · STD 12 - 13. Nuclei
An unstable heavy nucleus at rest breaks into two nuclei which move away with velocities in the ratio of \(8:27\). The ratio of the radii of the nuclei (assumed to be spherical ) is
- A \(8 : 27\)
- B \(2 : 3\)
- C \(3 : 2\)
- D \(4:9\)
Answer & Solution
Correct Answer
(C) \(3 : 2\)
Step-by-step Solution
Detailed explanation
Let heavy nucleus breaks into two nuclei of mass \(m_{1}\) and \(m_{2}\) and move away with velocities \({V}_{1}^1\) and \(V_{2}^2\) respectively. According to question, \(\frac{V_{1}}{V_{2}}=\frac{8}{27}\) \(m_{1} V_{1}=m_{2} V_{2}\) (Law of momentum conservation)…
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