JEE Mains · Physics · STD 12 - 8. Electromagnetic waves
A plane electromagnetic wave of frequency \(50\, MHz\) travels in free space along the positive \(x-\) direction. At a particular point in space and time, \(\vec E = 6.3\,\hat j\,V/m\) . The corresponding magnetic field \(\vec B\), at that point will be
- A \(18.9 \times {10^{ - 8}}\,\hat kT\)
- B \(2.1 \times {10^{ - 8}}\,\hat kT\)
- C \(6.3 \times {10^{ - 8}}\,\hat kT\)
- D \(18.9 \times {10^{ 8}}\,\hat kT\)
Answer & Solution
Correct Answer
(B) \(2.1 \times {10^{ - 8}}\,\hat kT\)
Step-by-step Solution
Detailed explanation
\(\frac{E}{B}=C\) \(B=\frac{E}{C}=\frac{6.3 \times 10^{27}}{3 \times 10^{8}}=2.1 \times 10^{19}\)
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