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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2017
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  • MCQ

An observer is moving with half the speed of light towards a stationary microwave source emitting waves at frequency \(10\ GHz\). What is the frequency of the microwave measured by the observer?.......\(GHz\) ( speed of light \(= 3 \times  10^8 \) \(ms^{-1}\))

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Answer & Solution

Correct Answer

(C) \(17.3\) 

Step-by-step Solution

Detailed explanation

Use relativistic doppler's effect as velocity of observer is not small as compared to light

\(f=f_{0} \sqrt{\frac{c+v}{c+v}}\) ; \(V=\) relative speed of approach

\(f_{0}=10\, \mathrm{GHz}\)

\(\therefore f=10 \sqrt{\frac{c+\frac{c}{2}}{c-\frac{c}{2}}}=10 \sqrt{3}=17.3\, \mathrm{GHz}\)

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