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JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
As shown in the figure, a point charge \(Q\) is placed at the centre of conducting spherical shell of inner radius a and outer radius \(b\). The electric field due to charge \(Q\) in three different regions I, II and III is given by: \(( I : r < a , II : a < r < b , III : r > b )\)
- A \(E _{ I }=0, E _{ II }=0, E _{ III } \neq 0\)
- B \(E _{ I } \neq 0, E _{ II }=0, E _{ III } \neq 0\)
- C \(E _{ I } \neq 0, E _{ II }=0, E _{ III }=0\)
- D \(E _{ I }=0, E _{ II }=0, E _{ III }=0\)
Answer & Solution
Correct Answer
(B) \(E _{ I } \neq 0, E _{ II }=0, E _{ III } \neq 0\)
Step-by-step Solution
Detailed explanation
Electric field inside material of conductor is zero.
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