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JEE Mains · Physics · STD 11 - Gravitation
  • JEE Mains 2023
  • Medium
  • MCQ

A body is released from a height equal to the radius ( \(R\) ) of the earth. The velocity of the body when it strikes the surface of the earth will be : (Given \(g\) = acceleration due to gravity on the earth.)

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Answer & Solution

Correct Answer

(A) \(\sqrt{g R}\)

Step-by-step Solution

Detailed explanation

By conservation of mechanical energy

\(U _{ i }+ K _{ i }= U _{ f }+ K _{ i }\)

\(-\frac{ GMm }{2 R }+0=-\frac{ GMm }{ R }+\frac{1}{2} mv ^2\)

\(\frac{ GMm }{2 R }=\frac{1}{2} mv ^2\)

\(v =\sqrt{\frac{ GM }{ R }}=\sqrt{ gR }\)

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