JEE Mains · Physics · STD 11 - Gravitation
- JEE Mains 2023
- Medium
- MCQ
A body is released from a height equal to the radius ( \(R\) ) of the earth. The velocity of the body when it strikes the surface of the earth will be : (Given \(g\) = acceleration due to gravity on the earth.)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(\sqrt{g R}\)
Step-by-step Solution
Detailed explanation
By conservation of mechanical energy
\(U _{ i }+ K _{ i }= U _{ f }+ K _{ i }\)
\(-\frac{ GMm }{2 R }+0=-\frac{ GMm }{ R }+\frac{1}{2} mv ^2\)
\(\frac{ GMm }{2 R }=\frac{1}{2} mv ^2\)
\(v =\sqrt{\frac{ GM }{ R }}=\sqrt{ gR }\)
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