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JEE Mains · Physics · STD 11 - 13. oscillations

The angular frequency of the damped oscillator is given by, \(\omega  = \sqrt {\left( {\frac{k}{m} - \frac{{{r^2}}}{{4{m^2}}}} \right)} \) where \(k\) is the spring constant, \(m\) is the mass of the oscillator and \(r\) is the damping constant. If the ratio \(\frac{{{r^2}}}{{mk}}\) is \(8\%\), the change in time period compared to the undamped oscillator is approximately as follows

  1. A increases by \(1\%\)
  2. B increases by \(8\%\)
  3. C decreases by \(1\%\) 
  4. D decreases by \(8\%\)
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Answer & Solution

Correct Answer

(A) increases by \(1\%\)

Step-by-step Solution

Detailed explanation

The change in time period compared to the undamped oscillator increases by \(1\%\)
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