JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
A parallel plate capacitor with plate area \('A'\) and distance of separation \('d'\) is filled with a dielectric. What is the capacity of the capacitor when permittivity of the dielectric varies as : \(\varepsilon(x)=\varepsilon_{0}+k x, \text { for }\left(0\,<\,x \leq \frac{d}{2}\right)\) \(\varepsilon(x)=\varepsilon_{0}+k(d-x)\), for \(\left(\frac{d}{2} \leq x \leq d\right)\)
- A \(0\)
- B \(\frac{{kA}}{2 \ln \left(\frac{2 \varepsilon_{0}+{kd}}{2 \varepsilon_{0}}\right)}\)
- C \(\left(\varepsilon_{0}+\frac{{kd}}{2}\right)^{2 / / {kA}}\)
- D \(\frac{{kA}}{2} \ln \left(\frac{2 \varepsilon_{0}}{2 \varepsilon_{0}-{kd}}\right)\)
Answer & Solution
Correct Answer
(B) \(\frac{{kA}}{2 \ln \left(\frac{2 \varepsilon_{0}+{kd}}{2 \varepsilon_{0}}\right)}\)
Step-by-step Solution
Detailed explanation
Taking an element of width \(dx\) at a distance \(x(x < d / 2)\) from left plate \(dC =\frac{\left(\varepsilon_{0}+ kx \right) A }{ dx }\) Capacitance of half of the capacitor…
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