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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2018
  • Hard
  • MCQ

A convergent doublet of separated lenses, corrected for spherical aberration, has resultant focal length of \(10\,cm\). The separation between the two lenses is \(2\,cm\). The focal lengths of the component lenses

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Answer & Solution

Correct Answer

(A) \(18\,cm, 20\,cm\)

Step-by-step Solution

Detailed explanation

For minimum spherical aberration separation

\(d \,= f_1-f_2\, = 2\,cm\)

Resultant focal lenght \(=F\,= 10\,cm\)

Using \(\frac{1}{F} = \frac{1}{{{f_1}}} + \frac{1}{{{f_2}}} - \frac{d}{{{f_1}{f_2}}}\) and solving we get \(f_1\), \(f_2\) \(18\,cm\) and \(20\,cm\) respectively

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