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JEE Mains · Maths · STD 11 - 14. probability

If \(10\) different balls are to be placed in \(4\) distinct boxes at random, then the probability that two of these boxes contain exactly \(2\) and \(3\) balls is 

  1. A \(\frac{945}{2^{11}}\)
  2. B \(\frac{965}{2^{11}}\)
  3. C \(\frac{945}{2^{10}}\)
  4. D \(\frac{965}{2^{10}}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{945}{2^{10}}\)

Step-by-step Solution

Detailed explanation

Total ways \(=4^{10}=\mathrm{n}\) Number of ways placing exactly 2 and 3 balls in two of these boxes \(=^{4} \mathrm{C}_{2} \times \frac{ 5!}{ 2! {3!}} \times 2! \times^{10} \mathrm{C}_{5} \times 2^{5}=\mathrm{m}\) Required probability…
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