JEE Mains · Physics · STD 11 - 7. gravitation
The height of any point \(P\) above the surface of earth is equal to diameter of earth. The value of acceleration due to gravity at point \(P\) will be : (Given \(g=\) acceleration due to gravity at the surface of earth)
- A \(g / 2\)
- B \(g / 4\)
- C \(g / 3\)
- D \(g / 9\)
Answer & Solution
Correct Answer
(D) \(g / 9\)
Step-by-step Solution
Detailed explanation
\(g =\frac{ Gm }{ r ^{2}}\) \(g ^{\prime}=\frac{ Gm }{(3 r )^{2}}\) \(g ^{\prime}=\frac{ Gm }{9 r ^{2}}\) \(g ^{\prime}=\frac{ g }{9}\)
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