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JEE Mains · Maths · STD 12 - 10. vector algebra

Let \(\vec{a}, \vec{b}\) and \(\vec{c}\) be three non-zero vectors such that \(\vec{b}\) and \(\vec{c}\) are non-collinear if \(\vec{a}+5 \vec{b}\) is collinear with \(\overrightarrow{\mathrm{c}}, \overrightarrow{\mathrm{b}}+6 \overrightarrow{\mathrm{c}}\) is collinear with \(\overrightarrow{\mathrm{a}}\) and \(\vec{a}+\alpha \vec{b}+\beta \vec{c}=\overrightarrow{0}\), then \(\alpha+\beta\) is equal to

  1. A \(35\)
  2. B \(30\)
  3. C \(-30\)
  4. D \(-25\)
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Answer & Solution

Correct Answer

(A) \(35\)

Step-by-step Solution

Detailed explanation

\( \overrightarrow{\mathrm{a}}+5 \mathrm{~b}=\lambda \overrightarrow{\mathrm{c}} \) \( \overrightarrow{\mathrm{b}}+6 \overrightarrow{\mathrm{c}}=\mu \overrightarrow{\mathrm{a}}\) Eliminating \(\vec{a}\)…
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