JEE Mains · Physics · STD 12 - 10. Wave optics
A parallel beam of monochromatic light of wavelength \(600 \mathrm{~nm}\) passes through single slit of \(0.4 \mathrm{~mm}\) width. Angular divergence corresponding to second order minima would be _______ \(\times 10^{-3} \mathrm{rad}\).
- A \(6\)
- B \(8\)
- C \(5\)
- D \(9\)
Answer & Solution
Correct Answer
(A) \(6\)
Step-by-step Solution
Detailed explanation
\(\sin \theta=\theta=\frac{2 \lambda}{b}\) \(=\frac{2 \times 600 \times 10^{-9}}{4 \times 10^{-4}}=3 \times 10^{-3} \mathrm{rad}\) \(\text { Total divergence }=(3+3) \times 10^{-3}=6 \times 10^{-3} \mathrm{rad}\)
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