JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
The current of \(5 \mathrm{~A}\) flows in a square loop of sides \(1\) \(\mathrm{m}\) is placed in air. The magnetic field at the centre of the loop is \(\mathrm{X} \sqrt{2} \times 10^{-7} \mathrm{~T}\). The value of \(\mathrm{X}\) is _______.
- A \(35\)
- B \(40\)
- C \(45\)
- D \(50\)
Answer & Solution
Correct Answer
(B) \(40\)
Step-by-step Solution
Detailed explanation
\(B=4 \times \frac{\mu_0 i}{4 \pi(1 / 2)}\left(\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}\right)\) \(=4 \times 10^{-7} \times 5 \times 2 \times \sqrt{2}\) \(=40 \sqrt{2} \times 10^{-7} \mathrm{~T}\)
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