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JEE Mains · Physics · STD 12 - Moving charges and magnetism
  • JEE Mains 2024
  • Hard
  • Numerical

The current of \(5 \mathrm{~A}\) flows in a square loop of sides \(1\) \(\mathrm{m}\) is placed in air. The magnetic field at the centre of the loop is \(\mathrm{X} \sqrt{2} \times 10^{-7} \mathrm{~T}\). The value of \(\mathrm{X}\) is _______.

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Answer & Solution

Correct Answer

(B) \(40\)

Step-by-step Solution

Detailed explanation

\(B=4 \times \frac{\mu_0 i}{4 \pi(1 / 2)}\left(\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}\right)\)

\(=4 \times 10^{-7} \times 5 \times 2 \times \sqrt{2}\)

\(=40 \sqrt{2} \times 10^{-7} \mathrm{~T}\)

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