JEE Mains · Physics · STD 12 - 1. Electric charges and fields
\(\sigma\) is the uniform surface charge density of a thin spherical shell of radius \(R\). The electric field at any point on the surface of the spherical shell is _______.
- A \(\sigma / \epsilon_0 R\)
- B \(\sigma / 2 \in_0\)
- C \(\sigma / \epsilon_0\)
- D \(\sigma / 4 \in_0\)
Answer & Solution
Correct Answer
(C) \(\sigma / \epsilon_0\)
Step-by-step Solution
Detailed explanation
By Gauss law \(\int \vec{E} \cdot d \vec{A}=\frac{q_{\text {in }}}{\varepsilon_0}\) \(\mathrm{EdA}=\frac{\sigma \times \mathrm{dA}}{\varepsilon_0}\) \(\mathrm{E}=\frac{\sigma}{\varepsilon_0}\)
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