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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2026
  • Easy
  • MCQ

In an experiment the values of two spring constants were measured as \(k _1=(10 \pm 0.2) N / m\)
and \(k _2=(20 \pm 0.3) N / m\). If these springs are connected in parallel, then the percentage error in equivalent spring constant is :

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Answer & Solution

Correct Answer

(D) 1.67%

Step-by-step Solution

Detailed explanation

For parallel combination of spring,
\( K_{eq} = K_{1} + K_{2} = 30 N/m \)
\( \Delta K_{eq} = \Delta K_{1} + \Delta K_{2} = 0.2 + 0.3 = 0.5 N/m \)
\(\therefore \quad\) %Error in \(K =\frac{0.5}{30} \times 100=1.67 \%\)
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