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JEE Mains · Physics · STD 12 - Nuclei
  • JEE Mains 2023
  • Medium
  • Numerical

A nucleus with mass number \(242\) and binding energy per nucleon as \(7.6\,MeV\) breaks into fragment each with mass number \(121\) . If each fragment nucleus has binding energy per nucleon as \(8.1\,MeV\), the total gain in binding energy is \(........MeV\)

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Answer & Solution

Correct Answer

(B) \(121\)

Step-by-step Solution

Detailed explanation

Initial binding energy \(=242 \times 7.6\,MeV\)

Final binding energy

\(=121 \times 8.1\,MeV +121 \times 8.1\,MeV\)

\(=242 \times 8.1\,MeV\)

Total gain in binding energy

\(=242(8.1-7.6)=121\,MeV\)

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