JEE Mains · Physics · STD 12 - Nuclei
- JEE Mains 2023
- Medium
- Numerical
A nucleus with mass number \(242\) and binding energy per nucleon as \(7.6\,MeV\) breaks into fragment each with mass number \(121\) . If each fragment nucleus has binding energy per nucleon as \(8.1\,MeV\), the total gain in binding energy is \(........MeV\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(121\)
Step-by-step Solution
Detailed explanation
Initial binding energy \(=242 \times 7.6\,MeV\)
Final binding energy
\(=121 \times 8.1\,MeV +121 \times 8.1\,MeV\)
\(=242 \times 8.1\,MeV\)
Total gain in binding energy
\(=242(8.1-7.6)=121\,MeV\)
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