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JEE Mains · Physics · STD 11 - Kinetic theory of gases
  • JEE Mains 2019
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A mixture of \(2\, moles\) of helium gas (atomic mass \(= 4\, u\)), and \(1\, mole\) of argon gas (atomic mass \(= 40\, u\)) is kept at \(300\, K\) in a container. The ratio of their rms speeds \(\left[ {\frac{{{V_{rms}}{\rm{(helium)}}}}{{{V_{rms}}{\rm{(argon)}}}}} \right]\), is close to

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Correct Answer

(A) \(3.16\)

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\(\frac{\left(\mathrm{V}_{\mathrm{RMS}}\right)_{\mathrm{He}}}{\left(\mathrm{V}_{\mathrm{RMS}}\right)_{\mathrm{Ar}}} =\sqrt{\frac{\mathrm{M}_{\mathrm{Ar}}}{\mathrm{M}_{\mathrm{He}}}} \)

\(=\sqrt{\frac{40}{4}}=\sqrt{10}=3.16\)

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