JEE Mains · Physics · STD 11 - Kinetic theory of gases
- JEE Mains 2019
- Medium
- MCQ
A mixture of \(2\, moles\) of helium gas (atomic mass \(= 4\, u\)), and \(1\, mole\) of argon gas (atomic mass \(= 40\, u\)) is kept at \(300\, K\) in a container. The ratio of their rms speeds \(\left[ {\frac{{{V_{rms}}{\rm{(helium)}}}}{{{V_{rms}}{\rm{(argon)}}}}} \right]\), is close to
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Answer & Solution
Correct Answer
(A) \(3.16\)
Step-by-step Solution
Detailed explanation
\(\frac{\left(\mathrm{V}_{\mathrm{RMS}}\right)_{\mathrm{He}}}{\left(\mathrm{V}_{\mathrm{RMS}}\right)_{\mathrm{Ar}}} =\sqrt{\frac{\mathrm{M}_{\mathrm{Ar}}}{\mathrm{M}_{\mathrm{He}}}} \)
\(=\sqrt{\frac{40}{4}}=\sqrt{10}=3.16\)
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