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JEE Mains · Physics · STD 11 - Fluid mechanics
  • JEE Mains 2023
  • Medium
  • MCQ

A small ball of mass \(M\) and density \(\rho\) is dropped in a viscous liquid of density \(\rho_0\). After some time, the ball falls with a constant velocity. What is the viscous force on the ball ?

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Answer & Solution

Correct Answer

(A) \(F=\mathrm{Mg}\left(1-\frac{\rho_0}{\rho}\right)\)

Step-by-step Solution

Detailed explanation

For constant velocity \(F_{\text {net }}=0\)

\(\mathrm{F}_{\mathrm{vis}}+\rho_0 \mathrm{vg}=\rho \mathrm{vg}\)

\(\mathrm{F}_{\mathrm{vis}}=\left(\rho-\rho_0\right) \mathrm{vg}\)

\(=\rho \mathrm{vg}\left(1-\frac{\rho_0}{\rho}\right)\)

\(=\mathrm{Mg}\left(1-\frac{\rho_0}{\rho}\right)\)

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