JEE Mains · Physics · STD 12 - 5. Magnetism and matter
A magnetic needle of magnetic moment \(6.7 \times 10^{-2} \) \(Am^2\) and moment of inertia \(7.5 \times 10^{-6}\) \( kgm^2\) is performing simple harmonic oscillations in a magnetic field of \(0.01\ T\). Time taken for \(10\) complete oscillations is.....\(s\)
- A \(6.65\)
- B \(8.89 \)
- C \(6.98\)
- D \(8.76 \)
Answer & Solution
Correct Answer
(A) \(6.65\)
Step-by-step Solution
Detailed explanation
Given : Magnetic moment, \(M=6.7 \times 10^{-2}\, \mathrm{Am}^{2}\) Magnetic field, \(\mathrm{B}=0.01\, \mathrm{T}\) Moment of inertia, \(I=7.5 \times 10^{-6}\, \mathrm{Kgm}^{2}\) \(\text { Using, } T =2 \pi \sqrt{\frac{I}{M B}} \)…
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