JEE Mains · Physics · STD 12 - Moving charges and magnetism
- JEE Mains 2022
- Medium
- Numerical
Two \(10 \; cm\) long, straight wires, each carrying a current of \(5 \; A\) are kept parallel to each other. If each wire experienced a force of \(10^{-5} \; N\), then separation between the wires is \(\dots \; cm\).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(5\)
Step-by-step Solution
Detailed explanation
It should be mentioned, \(10 \; cm\) wire is part of long wire.
Force experienced by unit length of wire
\(=\frac{\mu_{0} I _{1} I _{2}}{2 \pi d }, I _{1}= I _{2}=5 \; A\)
Force experienced by wires of length \(10 \; cm\)
\(=\frac{\mu_{0} I _{1} I _{2}}{2 \pi d } \times 10 \times 10^{-2}\)
\(10^{-5}=\frac{2 \times 10^{-7} \times 5 \times 5}{ d } \times 10 \times 10^{-2}\)
\(d =50 \times 10^{-3} \; m\)
\(d =50 \times 10^{-1} cm =5 \; cm\)
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