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JEE Mains · Physics · STD 12 - Moving charges and magnetism
  • JEE Mains 2022
  • Medium
  • Numerical

Two \(10 \; cm\) long, straight wires, each carrying a current of \(5 \; A\) are kept parallel to each other. If each wire experienced a force of \(10^{-5} \; N\), then separation between the wires is \(\dots \; cm\).

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Answer & Solution

Correct Answer

(C) \(5\)

Step-by-step Solution

Detailed explanation

It should be mentioned, \(10 \; cm\) wire is part of long wire.

Force experienced by unit length of wire

\(=\frac{\mu_{0} I _{1} I _{2}}{2 \pi d }, I _{1}= I _{2}=5 \; A\)

Force experienced by wires of length \(10 \; cm\)

\(=\frac{\mu_{0} I _{1} I _{2}}{2 \pi d } \times 10 \times 10^{-2}\)

\(10^{-5}=\frac{2 \times 10^{-7} \times 5 \times 5}{ d } \times 10 \times 10^{-2}\)

\(d =50 \times 10^{-3} \; m\)

\(d =50 \times 10^{-1} cm =5 \; cm\)

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