JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A charged particle carrying charge \(1\,\mu C\) is moving with velocity \((2 \hat{ i }+3 \hat{ j }+4 \hat{ k })\, ms ^{-1} .\) If an external magnetic field of \((5 \hat{ i }+3 \hat{ j }-6 \hat{ k }) \times 10^{-3}\, T\) exists in the region where the particle is moving then the force on the particle is \(\overline{ F } \times 10^{-9} N\). The vector \(\overrightarrow{ F }\) is :
- A \(-0.30 \hat{ i }+0.32 \hat{ j }-0.09 \hat{ k }\)
- B \(-300 \hat{ i }+320 \hat{ j }-90 \hat{ k }\)
- C \(-30 \hat{ i }+32 \hat{ j }-9 \hat{ k }\)
- D \(-3.0 \hat{ i }+3.2 \hat{ j }-0.9 \hat{ k }\)
Answer & Solution
Correct Answer
(C) \(-30 \hat{ i }+32 \hat{ j }-9 \hat{ k }\)
Step-by-step Solution
Detailed explanation
\(\overrightarrow{ F }=q(\overrightarrow{ V } \times \overrightarrow{ B })\) (Force on charge particle moving in magnetic field) \(\overrightarrow{ V } \times \overrightarrow{ B }=(2 \hat{ i }+3 \hat{ j }+4 \hat{ k }) \times(5 \hat{ i }+3 \hat{ j }-6 \hat{ k }) \times 10^{-3}\)…
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