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JEE Mains · Physics · STD 11 - Motion in straight line
  • JEE Mains 2022
  • Medium
  • Numerical

A small toy starts moving from the position of rest under a constant acceleration. If it travels a distance of \(10 \,m\) in \(t \;s ,\) the distance travelled by the toy in the next \(t s\) will be .........\(m\)

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Answer & Solution

Correct Answer

(C) \(30\)

Step-by-step Solution

Detailed explanation

\(u =0, \quad\) Say acceleration is a

For \(ts\) \(\quad 10=\frac{1}{2} a t^{2}\)

For \(2 t s\)

\(10+ x =\frac{1}{2} a (2 t )^{2}\)

\(\frac{10+ x }{10}=\frac{4}{1}\)

\(x =30 \,m\)

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