JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
A light string passing over a smooth light fixed pulley connects two blocks of masses \(m_1\) and \(m_2\). If the acceleration of the system is \(g / 8\), then the ratio of masses is _______.
- A \(\frac{9}{7}\)
- B \(\frac{8}{1}\)
- C \(\frac{4}{3}\)
- D \(\frac{5}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{9}{7}\)
Step-by-step Solution
Detailed explanation
\(a=\frac{\left(m_1-m_2\right) g}{\left(m_1+m_2\right)}=\frac{g}{8}\) \(8 m_1-8 m_2=m_1+m_2\) \(7 m_1=9 m_2 \) \(\frac{m_1}{m_2}=\frac{9}{7}\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- A capacitor is discharging through a resistor \(R\). Consider in time \(t _{1}\), the energy stored in the capacitor reduces to half of its initial value and in time \(t_{2}\), the charge stored reduces to one eighth of its initial value. The ratio \(t_{1} / t_{2}\) will be ................JEE Mains 2022 Hard
- A current of \(30\) A each flows in opposite directions in two conducting wires, placed parallel to each other at a distance of \(8\) cm. The magnetic field at the mid point between the two wires is __________ \(\mu\)T. \(\left(\dfrac{\mu_0}{4\pi} = 10^{-7}\text{ N/A}^2\right)\)JEE Mains 2026 Medium
- A cube of metal is subjected to a hydrostatic pressure of \(4\;GPa.\) The percentage change in the length of the side of the cube is close to.......\(\%\)
(Given bulk modulus of metal, \(B =8 \times 10^{10}\, Pa\) )JEE Mains 2020 Medium - A horse rider covers half the distance with \(5\,m / s\) speed. The remaining part of the distance was travelled with speed \(10\,m / s\) for half the time and with speed \(15 m / s\) for other half of the time. The mean speed of the rider averaged over the whole time of motion is \(\frac{x}{7}\,m / s\). The value of \(x\) is
JEE Mains 2023 Hard - Two balls with same mass and initial velocity, are projected at different angles in such a way that maximum height reached by first ball is 8 times higher than that of the second ball. \(T_1\) and \(T_2\) are the total flying times of first and second ball, respectively, then the ratio of \(T_1\) and \(T_2\) is :JEE Mains 2025 Easy
- Two planets have masses \(M\) and \(16\, M\) and their radii are \(a\) and \(2\, a\) respectively. The separation between the centres of the planets is \(10\, a.\) A body of mass \(m\) is fired from the surface of the larger planet towards the smaller planet along the line joining their centres. For the body to be able to reach at the surface of smaller planet, the minimum firing speed needed isJEE Mains 2020 Hard
More PYQs from JEE Mains
- The plane through the intersection of the plane \(x + y + z = 1\) and \(2x + 3y + z - 4 = 0\) and parallel to \(y -\) axis also pass through the pointJEE Mains 2019 Hard
- If \({\left( {10} \right)^9} + 2{\left( {11} \right)^1}{\left( {10} \right)^8} + 3{\left( {11} \right)^2}{\left( {10} \right)^7} + ..\;.\;.\;.\; + 10\left( {{{11}^9}} \right) = \;k{\left( {10} \right)^9}\) ,then \(k \) is equal toJEE Mains 2014 Hard
- The remainder, when \(7^{103}\) is divided by \(17\) is \(..........\).JEE Mains 2023 Hard
- Using equipartition of energy, the specific heat (in \(J\, kg^{-1}\, K^{-1}\) ) of aluminium at room temperature can be estimated to be ( atomic weight of aluminium \(= 27\))JEE Mains 2015 Hard
- Let \(S_1=\{z \in C:|z| \leq 5\}\), \(S_2=\left\{z \in C: I m\left(\frac{z+1-\sqrt{3} i}{1-\sqrt{3} i}\right) \geq 0\right\}\) and \(\mathrm{S}_3=\{\mathrm{z} \in \mathrm{C}: \operatorname{Re}(\mathrm{z}) \geq 0\}\). Then the area of the region \(S_1 \cap S_2 \cap S_3\) is:JEE Mains 2024 Hard
- An open glass tube is immersed in mercury in such a way that a length of \(8\ cm\) extends above the mercury level. The open end of the tube is then closed and sealed and the tube is raised vertically up by additional \(46\ cm\). What will be length of the air column above mercury in the tube now ....... \(cm\) ? ( Atmospheric pressure = \(76\ cm\) of \(Hg\))JEE Mains 2014 Medium