JEE Mains · Physics · STD 11 - 10.2 transmission of heat
Rods x and y of equal dimensions but of different materials are joined as shown in figure. Temperatures of end points A and F are maintained at \( 100^{\circ}C \) and \( 40^{\circ}C \) respectively. Given the thermal conductivity of rod x is three times of that of rod y, the temperature at junction points B and E are (close to):
- A \( 89^{\circ}C \) and \( 73^{\circ}C \) respectively
- B \( 80^{\circ}C \) and \( 60^{\circ}C \) respectively
- C \( 80^{\circ}C \) and \( 70^{\circ}C \) respectively
- D \( 60^{\circ}C \) and \( 45^{\circ}C \) respectively
Answer & Solution
Correct Answer
(A) \( 89^{\circ}C \) and \( 73^{\circ}C \) respectively
Step-by-step Solution
Detailed explanation
Let \(\left[ R =\frac{\ell}{3 KA }\right]\) \(\left[ H =\frac{100-40}{\frac{11 R }{2}}\right]\) \(\quad\) ... (1) \(H=\frac{100-T_B}{R}\)\(\quad\) ... (2) \(H =\frac{ T _{ E }-40}{3 R }\)\(\quad\) ... (3) using (1) and (2) \(120=1100-11 T_{ A }\) \(T _{ B }=89^{\circ} C\) using…
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