JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2020
- Hard
- Numerical
A light ray enters a solid glass sphere of refractive index \(\mu=\sqrt{3}\) at an angle of incidence \(60^{\circ}\). The ray is both reflected and refracted at the farther surface of the sphere. The angle (in degrees) between the reflected and refracted rays at this surface is......
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(90\)
Step-by-step Solution
Detailed explanation
By Snell's law at \(A\)
\(1 \times \sin 60^{\circ}=\sqrt{3} \times \sin \theta\)
\(\frac{\sqrt{3}}{2}=\sqrt{3} \sin \theta\)
\(\sin \theta=\frac{1}{2} \Rightarrow \theta=30^{\circ}\)
So at \(B:\)
\(\theta+60^{\circ}+\alpha=180^{\circ}\)
\(30^{\circ}+60^{\circ}+\alpha=180^{\circ}\)
\(\alpha=90^{\circ}\)
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