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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2020
  • Hard
  • Numerical

A light ray enters a solid glass sphere of refractive index \(\mu=\sqrt{3}\) at an angle of incidence \(60^{\circ}\). The ray is both reflected and refracted at the farther surface of the sphere. The angle (in degrees) between the reflected and refracted rays at this surface is......

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Answer & Solution

Correct Answer

(B) \(90\)

Step-by-step Solution

Detailed explanation

By Snell's law at \(A\)

\(1 \times \sin 60^{\circ}=\sqrt{3} \times \sin \theta\)

\(\frac{\sqrt{3}}{2}=\sqrt{3} \sin \theta\)

\(\sin \theta=\frac{1}{2} \Rightarrow \theta=30^{\circ}\)

So at \(B:\)

\(\theta+60^{\circ}+\alpha=180^{\circ}\)

\(30^{\circ}+60^{\circ}+\alpha=180^{\circ}\)

\(\alpha=90^{\circ}\)