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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2020
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  • MCQ

A double convex lens has power \(P\) and same radii of curvature \(R\) of both the surfaces. The radius of curvature of a surface of a plano-convex lens made of the same material with power \(1.5P\) is ......\(R\)

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Answer & Solution

Correct Answer

(D) \(0.33\)

Step-by-step Solution

Detailed explanation

\(R _{1}= R _{2}= R\)

Power \((P)\)

Refractive index is assume \(\left(\mu_{\ell}\right)\)

\(P =\frac{1}{ f }=\left(\mu_{\ell}-1\right)\left(\frac{2}{ R }\right)\) \(...(i)\)

\(P ^{\prime}=\frac{1}{ f ^{\prime}}=\left(\mu_{\ell}-1\right)\left(\frac{1}{ R ^{\prime}}\right)\)\(....(ii)\)

\(P ^{\prime}=\frac{3}{2} P\)

\(\left(\mu_{\ell}-1\right)\left(\frac{1}{ R ^{\prime}}\right)=\mu \frac{3}{2}\left(\mu_{\ell}-1\right)\left(\frac{2}{ R }\right)\)

\(\therefore \quad R ^{\prime}=\frac{ R }{3}\)

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