JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
Two long, straight wires carry equal currents in opposite directions as shown in figure. The separation between the wires is \(5.0 \mathrm{~cm}\). The magnitude of the magnetic field at a point \(P\) midway between the wires is __________\(\mu \mathrm{T}\) (Given : \(\mu_0=4 \pi \times 10^{-7} \mathrm{TmA}^{-1}\) )
- A \(65\)
- B \(34\)
- C \(14\)
- D \(160\)
Answer & Solution
Correct Answer
(D) \(160\)
Step-by-step Solution
Detailed explanation
\( B=\left(\frac{\mu_0 i}{2 \pi \mathrm{a}}\right) \times 2=\frac{4 \pi \times 10^{-7} \times 10}{\pi \times\left(\frac{5}{2} \times 10^{-2}\right)} \) \( =16 \times 10^{-5}=160 \mu \mathrm{T}\)
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