JEE Mains · Physics · STD 11 - 3.2 motion in plane
A gun mounted on the ground fires bullets in all directions with same speed. The farthest distance the bullets could reach is \(6.4\) m. The speed of the bullets from the gun is ______ m/s.
(take \(g=10\) m/s\(^2\))
- A 5
- B 6
- C 7
- D 8
Answer & Solution
Correct Answer
(D) 8
Step-by-step Solution
Detailed explanation
The maximum horizontal range of a projectile is given by \(R_{\text{max}} = \dfrac{u^2}{g}\). Given \(R_{\text{max}} = 6.4\) m and \(g = 10\) m/s\(^2\). Substituting the values: \(6.4 = \dfrac{u^2}{10}\) \(u^2 = 64\) \(u = 8\) m/s. Answer: \(8\)
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