JEE Mains · Physics · STD 11 - 11. thermodynamics
A Carnot engine absorbs \(1000\,J\) of heat energy from a reservoir at \(127\,^oC\) and rejects \(600\,J\) of heat energy during each cycle. The efficiency of engine and temperature of sink will be
- A \(20\%\) and \(- 43\,^oC\)
- B \(40\%\) and \(- 33\,^oC\)
- C \(50\%\) and \(- 20\,^oC\)
- D \(70\%\) and \(- 10\,^oC\)
Answer & Solution
Correct Answer
(B) \(40\%\) and \(- 33\,^oC\)
Step-by-step Solution
Detailed explanation
Given: \(Q_1=1000 J\) \(Q_2=600 J\) \({T_1} = {127^ \circ }C = 400\,K\) \({T_2} = ?\) \(\eta = ?\) Efficiency of carnot engine, \(\eta = \frac{W}{Q_1} \times 100\% \) \(or,\,\,\eta = \frac{{{Q_2} - {Q_1}}}{{{Q_1}}} \times 100\% \)…
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