JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
The density of a material in \(SI\, units\) is \(128\, kg\, m^{-3}\). In certain units in which the unit of length is \(25\, cm\) and the unit of mass \(50\, g\), the numerical value of density of the material is
- A \(40\)
- B \(16\)
- C \(640\)
- D \(410\)
Answer & Solution
Correct Answer
(A) \(40\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{l} \frac{{128kg}}{{{m^3}}} = \frac{{125\left( {50g} \right)\left( {20} \right)}}{{{{\left( {25cm} \right)}^3}{{\left( 4 \right)}^3}}}\\ = \frac{{128}}{{64}}\left( {20} \right)units\\ = 40units \end{array}\)
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