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JEE Mains · Physics · STD 12 - 1. Electric charges and fields

A dipole with two electric charges of \(2 \mu \mathrm{C}\) magnitude each, with separation distance \(0.5 \mu \mathrm{~m}\), is placed between the plates of a capacitor such that its axis is parallel to an electric field established between the plates when a potential difference of 5 V is applied. Separation between the plates is 0.5 mm. If the dipole is rotated by \(30^{\circ}\) from the axis, it tends to realign in the direction due to a torque. The value of torque is :

  1. A \(5 \times 10^{-9} \mathrm{Nm}\)
  2. B \(5 \times 10^{-3} \mathrm{Nm}\)
  3. C \(2.5 \times 10^{-12} \mathrm{Nm}\)
  4. D \(2.5 \times 10^{-9} \mathrm{Nm}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(5 \times 10^{-9} \mathrm{Nm}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \mathrm{E}=\frac{\mathrm{v}}{\mathrm{~d}}=\frac{5}{5 \times 10^{-4}}=10^4 \mathrm{~V} / \mathrm{m} \\ & \tau=\mathrm{PE} \sin \theta \end{aligned}\) Where \(\mathrm{P}=\mathrm{qa}=2 \times 10^{-6} \times 5 \times 10^{-7}\)…
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