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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2019
  • Medium
  • Numerical

In the circuit shown, the potential difference between \(A\) and \(B\) is ............. \(V\)

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Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

Potential difference across \(AB\) will be equal to battery equivalent across \(CD\).

\( V_{A B} =V_{C D}=\frac{\frac{E_{1}}{r_{1}}+\frac{E_{2}}{r_{2}}+\frac{E_{3}}{r_{3}}}{\frac{1}{r_{1}}+\frac{1}{r_{2}}+\frac{1}{r_{3}}}=\frac{\frac{1}{1}+\frac{2}{1}+\frac{3}{1}}{\frac{1}{1}+\frac{1}{1}+\frac{1}{1}} \)

\(=\frac{6}{3}=2\, V\)

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