JEE Mains · Physics · STD 12 - 1. Electric charges and fields
Two shorts dipoles \((A, B), A\) having charges \(\pm 2 \mu C\) and length 1 cm and \(B\) having charges \(\pm 4 \mu C\) and length 1 cm are placed with their centres 80 cm apart as shown in the figure. The electric field at a point \(P\), equi-distant from the centres of both dipoles is ___________ N/C.
- A \(\frac{9}{16}\sqrt{2}\times10^{5}\)
- B \(4.5 \sqrt{2}\times10^{4}\)
- C \(9\sqrt{2}\times10^{4}\)
- D \(\frac{9}{16}\sqrt{2}\times10^{4}\)
Answer & Solution
Correct Answer
(D) \(\frac{9}{16}\sqrt{2}\times10^{4}\)
Step-by-step Solution
Detailed explanation
\(\overrightarrow{ E }_2=-\frac{ KP _2}{ r ^3} ; E _1=-\frac{2 KP _1}{ r ^3}\) \(P_1=2 \times 10^{-6} \times 10^{-2}=2 \times 10^{-8}\) \(P_2=4 \times 10^{-6} \times 10^{-2}=4 \times 10^{-8}\)…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- \(AC\) alternating emf \(\mathrm{E}=110 \sqrt{2} \sin 100 \mathrm{t}\) volt is applied to a capacitor of \(2 \mu \mathrm{F}\), the rms value of current in the circuit is _______ \(\mathrm{mA}\).JEE Mains 2024 Hard
- If the potential barrier across a \(p - n\) junction is \(0.6\,V\). Then the electric field intensity, in the depletion region having the width of \(6 \times 10^{-6} m\), will be \(......\times 10^{5} N / C\).JEE Mains 2022 Easy
- A \(16\, \Omega\) wire is bend to form a square loop. A \(9 \,{V}\) supply having internal resistance of \(1 \,\Omega\) is connected across one of its sides. The potential drop across the diagonals of the square loop is \(.......\,\times 10^{-1} \,{V}\)JEE Mains 2021 Medium
- In the figure shown, what is the current (in Ampere) drawn from the battery ? You are given \(R_1 = 15\,\Omega \)\(,R _2 = 10\,\Omega ,\)\( R_3 = 20\,\Omega ,\)\( R_4 = 5\,\Omega ,\)\(R_5 = 25\,\Omega ,\)\(R_6 = 30\,\Omega , \)\(E = 15\,V\)
JEE Mains 2019 Medium - Two planets, \(A\) and \(B\) are orbiting a common star in circular orbits of radius \(R_A\) and \(R_B\), respectively, with \(R_B=2 R_A\). The planet \(B\) is \(4 \sqrt{2}\) times more massive than planet \(A\). The ratio \(\left(\frac{L_B}{L_A}\right)\) of angular momentum \(\left(L_B\right)\) of planet \(B\) to that of planet \(A\left(L_A\right)\) is closest to integer ________.JEE Mains 2025 Medium
- According to kinetic theory of gases, \(A\). The motion of the gas molecules freezes at \(0^{\circ} C\) \(B\). The mean free path of gas molecules decreases if the density of molecules is increased. \(C\). The mean free path of gas molecules increases if temperature is increased keeping pressure constant. \(D\). Average kinetic energy per molecule per degree of freedom is \(\frac{3}{2} k_{B} T\) (for monoatomic gases) Choose the most appropriate answer from the options given belowJEE Mains 2022 Medium
More PYQs from JEE Mains
- Match List-I with List-II.
List-I List-II (A) Isothermal (I) \(\Delta W(\text{work done}) = 0\) (B) Adiabatic (II) \(\Delta Q(\text{supplied heat}) = 0\) (C) Isobaric (III) \(\Delta U(\text{change in internal energy}) \neq 0\) (D) Isochoric (IV) \(\Delta U = 0\)
Choose the correct answer from the options given below :JEE Mains 2025 Easy - Let \(M\) and \(N\) be the number of points on the curve \(y^{5}-9 x y+2 x=0\), where the tangents to the curve are parallel to \(x\)-axis and \(y\)-axis, respectively. Then the value of \(M + N\) equals \(......\)JEE Mains 2022 Hard
- Rods x and y of equal dimensions but of different materials are joined as shown in figure. Temperatures of end points A and F are maintained at \( 100^{\circ}C \) and \( 40^{\circ}C \) respectively. Given the thermal conductivity of rod x is three times of that of rod y, the temperature at junction points B and E are (close to):
JEE Mains 2026 Easy - A series \(LCR\) circuit of \(R=5\, \Omega, L=20\, {mH}\) and \({C}=0.5 \,\mu \,{F}\) is connected across an \({AC}\) supply of \(250\, V\), having variable frequency. The power dissipated at resonance condition is \(.....\,\times 10^{2}\, {W}\)JEE Mains 2021 Medium
- If the equation of the normal to the curve \(y=\frac{x-a}{(x+b)(x-2)}\) at the point \((1,-3)\) is \(x-4 y=13\), then the value of \(a+b\) is equal to \(.......\).JEE Mains 2023 Hard
- Choose the correct option from the following options given belowJEE Mains 2022 Medium