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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2023
  • Easy
  • Numerical

A current of \(2\,A\) flows through a wire of crosssectional area \(25.0\,mm ^2\). The number of free electrons in a cubic meter are \(2.0 \times 10^{28}\). The drift velocity of the electrons is \(...............\times 10^{-6}\,ms ^{-1}\) (given, charge on electron \(=1.6 \times 10^{-19}\,C\) )

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Answer & Solution

Correct Answer

(B) \(25\)

Step-by-step Solution

Detailed explanation

Drift velocity \(v_d=\frac{I}{\text { neA }}\)

\(=\frac{2}{2 \times 10^{28} \times 1.6 \times 10^{-19} \times 25 \times 10^{-6}}\)

\(=25 \times 10^{-6}\,ms ^{-1}\)

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