JEE Mains · Physics · STD 12 - 3. current electricity
A current of \(2\,A\) flows through a wire of crosssectional area \(25.0\,mm ^2\). The number of free electrons in a cubic meter are \(2.0 \times 10^{28}\). The drift velocity of the electrons is \(...............\times 10^{-6}\,ms ^{-1}\) (given, charge on electron \(=1.6 \times 10^{-19}\,C\) )
- A \(24\)
- B \(25\)
- C \(23\)
- D \(89\)
Answer & Solution
Correct Answer
(B) \(25\)
Step-by-step Solution
Detailed explanation
Drift velocity \(v_d=\frac{I}{\text { neA }}\) \(=\frac{2}{2 \times 10^{28} \times 1.6 \times 10^{-19} \times 25 \times 10^{-6}}\) \(=25 \times 10^{-6}\,ms ^{-1}\)
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