JEE Mains · Physics · STD 12 - Electromagnetic waves
- JEE Mains 2022
- Medium
- MCQ
A beam of light travelling along \(X\)-axis is described by the electric field \(E _{ y }=900 \sin \omega( t - x / c )\). The ratio of electric force to magnetic force on a charge \(q\) moving along \(Y\)-axis with a speed of \(3 \times 10^{7}\,ms ^{-1}\) will be. [Given speed of light \(=3 \times 10^{8}\,ms ^{-1}\) ]
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(10: 1\)
Step-by-step Solution
Detailed explanation
\(E _{ y }=900 \sin \left(\omega t -\frac{\omega x }{ c }\right)\)
\(E _{0}=900\)
\(F _{ E }= q E _{0}\)
\(F _{ B }= qvB _{0}\)
\(\frac{ F _{ E }}{ F _{ B }}=\frac{ E _{0}}{ vB }=\frac{ c }{ v }=\frac{3 \times 10^{8}}{3 \times 10^{7}}=10: 1\)
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