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JEE Mains · Physics · STD 12 - Electromagnetic waves
  • JEE Mains 2022
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A beam of light travelling along \(X\)-axis is described by the electric field \(E _{ y }=900 \sin \omega( t - x / c )\). The ratio of electric force to magnetic force on a charge \(q\) moving along \(Y\)-axis with a speed of \(3 \times 10^{7}\,ms ^{-1}\) will be. [Given speed of light \(=3 \times 10^{8}\,ms ^{-1}\) ]

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Answer & Solution

Correct Answer

(C) \(10: 1\)

Step-by-step Solution

Detailed explanation

\(E _{ y }=900 \sin \left(\omega t -\frac{\omega x }{ c }\right)\)

\(E _{0}=900\)

\(F _{ E }= q E _{0}\)

\(F _{ B }= qvB _{0}\)

\(\frac{ F _{ E }}{ F _{ B }}=\frac{ E _{0}}{ vB }=\frac{ c }{ v }=\frac{3 \times 10^{8}}{3 \times 10^{7}}=10: 1\)

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