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JEE Mains · Physics · STD 12 - 8. Electromagnetic waves

A beam of light travelling along \(X\)-axis is described by the electric field \(E _{ y }=900 \sin \omega( t - x / c )\). The ratio of electric force to magnetic force on a charge \(q\) moving along \(Y\)-axis with a speed of \(3 \times 10^{7}\,ms ^{-1}\) will be. [Given speed of light \(=3 \times 10^{8}\,ms ^{-1}\) ]

  1. A \(1: 1\)
  2. B \(1: 10\)
  3. C \(10: 1\)
  4. D \(1: 2\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(10: 1\)

Step-by-step Solution

Detailed explanation

\(E _{ y }=900 \sin \left(\omega t -\frac{\omega x }{ c }\right)\) \(E _{0}=900\) \(F _{ E }= q E _{0}\) \(F _{ B }= qvB _{0}\) \(\frac{ F _{ E }}{ F _{ B }}=\frac{ E _{0}}{ vB }=\frac{ c }{ v }=\frac{3 \times 10^{8}}{3 \times 10^{7}}=10: 1\)
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