JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
Two capacitors of capacities \(2 {C}\) and \({C}\) are joined in parallel and charged up to potential \({V}\). The battery is removed and the capacitor of capacity \(C\) is filled completely with a medium of dielectric constant \({K}\). The potential difference across the capacitors will now be
- A \(\frac{3 V}{K}\)
- B \(\frac{{V}}{{K}}\)
- C \(\frac{3 V}{K+2}\)
- D \(\frac{{V}}{{K}+2}\)
Answer & Solution
Correct Answer
(C) \(\frac{3 V}{K+2}\)
Step-by-step Solution
Detailed explanation
\(V_{C}=\frac{2 C V+C V}{K C+2 C}\) \(V_{C}=\frac{3 V}{K+2}\)
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