JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
A cord of negligible mass is wound around the rim of a wheel supported by spokes with negligible mass. The mass of wheel is 10 kg and radius is 10 cm and it can freely rotate without any friction. Initially the wheel is at rest. If a steady pull of 20 N is applied on the cord, the angular velocity of the wheel, after the cord is unwound by 1 m , would be :
- A \(20 \mathrm{rad} / \mathrm{s}\)
- B \(30 \mathrm{rad} / \mathrm{s}\)
- C \(10 \mathrm{rad} / \mathrm{s}\)
- D \(0 \mathrm{rad} / \mathrm{s}\)
Answer & Solution
Correct Answer
(A) \(20 \mathrm{rad} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \mathrm{W}_{\mathrm{F}}=20 \times 1=20 \mathrm{~J} \\ & \therefore \quad \Delta \mathrm{KE}=20 \mathrm{~J}=\frac{1}{2} \mathrm{I} \omega^2 \\ & \mathrm{I}=\mathrm{MR}^2=10 \times 0.1^2=0.1 \mathrm{~kg} \mathrm{~m}^2 \\ & \therefore \quad 20=\frac{1}{2} \times…
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