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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
- JEE Mains 2022
- Easy
- MCQ
The equation \(\lambda=\frac{1.227}{ x } nm\) can be used to find the de-Brogli wavelength of an electron. In this equation \(x\) stands for : Where,\(m =\) mass of electron \(P =\) momentum of electron \(K =\) Kinetic energy of electron \(V =\) Accelerating potential in volts for electron
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(\sqrt{ V }\)
Step-by-step Solution
Detailed explanation
\(\lambda=\frac{ h }{ m v}\) (de-Broglie's wavelength)
\(\lambda \frac{ h }{\sqrt{2 m ( K \cdot E )}}\)
\(h =\frac{ h }{\sqrt{2 mqV }}\)
Putting the values of \(m ; q\)
We get \(\lambda=\frac{1 \cdot 22}{\sqrt{V}}\,nm\)
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