enEnglishhiहिन्दी
JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
The equation \(\lambda=\frac{1.227}{ x } nm\) can be used to find the de-Brogli wavelength of an electron. In this equation \(x\) stands for : Where,\(m =\) mass of electron \(P =\) momentum of electron \(K =\) Kinetic energy of electron \(V =\) Accelerating potential in volts for electron
- A \(\sqrt{ mK }\)
- B \(\sqrt{ P }\)
- C \(\sqrt{ K }\)
- D \(\sqrt{ V }\)
Answer & Solution
Correct Answer
(D) \(\sqrt{ V }\)
Step-by-step Solution
Detailed explanation
\(\lambda=\frac{ h }{ m v}\) (de-Broglie's wavelength) \(\lambda \frac{ h }{\sqrt{2 m ( K \cdot E )}}\) \(h =\frac{ h }{\sqrt{2 mqV }}\) Putting the values of \(m ; q\) We get \(\lambda=\frac{1 \cdot 22}{\sqrt{V}}\,nm\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- A particle executes simple harmonic motion between \(x =- A\) and \(x =+ A\). If time taken by particle to go from \(x=0\) to \(\frac{A}{2}\) is \(2 s\); then time taken by particle in going from \(x =\frac{ A }{2}\) to \(A\) is \(.........\,s\)JEE Mains 2023 Medium
- Interference pattern is observed at \('P'\) due to superimposition of two rays coming out from a source \('S'\) as shown in the figure. The value of \('I'\) for which maxima is obtained at \('P'\) is: ( \(R\) is perfect reflecting surface)
JEE Mains 2014 Hard - A uniform wire of length \(l\) of weight \(w\) is suspended from the roof with a weight of \(W\) at the other end. The stress in the wire at \(\dfrac{l}{3}\) distance from the top is \(\left(\dfrac{W}{A} + \dfrac{2}{\gamma}\dfrac{w}{A}\right)\), where, \(A\) is the cross sectional area of the wire. The value of \(\gamma\) is _______.JEE Mains 2026 Medium
- Consider a block kept on an inclined plane (inclined at \(45^{\circ}\) ) as shown in the figure. If the force required to just push it up the incline is \(2\) times the force required to just prevent it from sliding down, the coefficient of friction between the block and inclined plane \((\mu)\) is equal to
JEE Mains 2023 Hard - Current passing through a wire as function of time is given as \(\mathrm{I}(\mathrm{t})=0.02 \mathrm{t}+0.01 \mathrm{~A}\). The charge that will flow through the wire from \(t=1 s\) to \(t=2 s\) is :JEE Mains 2025 Medium
- A conducting wire of length \( l\) area of cross-section \(A\) and electric resistivity \(\rho\) is connected between the terminals of a battery. \(A\) potential difference \(V\) is developed between its ends, causing an electric current.If the length of the wire of the same material is doubled and the area of cross-section is halved, the resultant current would beJEE Mains 2021 Medium
More PYQs from JEE Mains
- A value of \(\theta\) for which \(\frac{{2 + 3isin\;\theta }}{{1 - 2i\sin \theta }}\) is purely imaginary, is:JEE Mains 2016 Medium
- If \(\frac{{dy}}{{dx}} + y\tan x = \sin 2x\) and \(y(0)\,=1\) , then \(y(\pi)\) is equal toJEE Mains 2014 Hard
- If \(x = x ( y )\) is the solution of the differential equation \(y \frac{d x}{d y}=2 x+y^{3}(y+1) e^{y}, x(1)=0\); then \(x(e)\) is equal toJEE Mains 2022 Hard
- The coordinates of centre of mass of a uniform flag shaped lamina (thin flat plate) of mass \(4\;kg\). (The coordinates of the same are shown in figure) are
JEE Mains 2020 Medium - An asteroid is moving directly towards the centre of the earth. When at a distance of \(10 \mathrm{R}\) (\(R\) is the radius of the earth) from the earths centre, it has a speed of \(12 \;\mathrm{km} / \mathrm{s}\). Neglecting the effect of earths atmosphere, what will be the speed of the asteroid when it hits the surface of the earth (escape velocity from the earth is \(11.2 \;\mathrm{km} / \mathrm{s}\) ) \(?\) Give your answer to the nearest integer in \(km/s\)JEE Mains 2020 Hard
- If the equation of the parabola with vertex \(\mathrm{V}\left(\frac{3}{2}, 3\right)\) and the directrix \(x+2 y=0\) is \(\alpha x^2+\beta y^2-\gamma x y-30 x-60 y+225=0\), then \(\alpha+\beta+\gamma\) is equal to :JEE Mains 2025 Easy