JEE Mains · Physics · STD 12 -Electromagnetic induction
- JEE Mains 2023
- Medium
- Numerical
A conducting circular loop is placed in a uniform magnetic field of \(0.4\,T\) with its plane perpendicular to the field. Somehow, the radius of the loop starts expanding at a constant rate of \(1\,mm / s\). The magnitude of induced emf in the loop at an instant when the radius of the loop is \(2\,cm\) will be \(...........\,\mu V\).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(50\)
Step-by-step Solution
Detailed explanation
\(\frac{ dr }{ dt }=10^{-3}\,m / s\)
\(\frac{ dA }{ dt }=2 \pi r \frac{ dr }{ dt }\)
\(\varepsilon=\left|\frac{- d \phi}{ dt }\right|=\left|\frac{ BdA }{ dt }\right|\)
\(=0.4 \times 2 \times \pi \times 2 \times 10^{-2} \times 10^{-3}\,V\)
\(=16 \pi\, \mu V =50.24\,\mu V\)
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