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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2021
  • Medium
  • Numerical

A zener diode having zener voltage \(8\, {V}\) and power dissipation rating of \(0.5\, {W}\) is connected across a potential divide arranged with maximum potential drop across zener diode is as shown in the diagram. The value of protective resistance \({R}_{{p}}\) is \(....\,\Omega\)

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Answer & Solution

Correct Answer

(C) \(192\)

Step-by-step Solution

Detailed explanation

\(P=V i\)

\(0.5=8 i\)

\(i=\frac{1}{16}\, A\)

\(E=20=8+i R_{p}\)

\(R_{P}=12 \times 16=192\, \Omega\)

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