JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
To know the resistance \(G\) of a galvanometer by half deflection method, a battery of \(emf\, V_E\) and resistance \(R\) is used to deflect the galvanometer by angle \(\theta \). If a shunt of resistance \(S\) is needed to get half deflection then \(G, R\) and \(S\) related by the equation
- A \(S (R+ G) = RG\)
- B \(2S (R+G)=RG\)
- C \(2G = S\)
- D \(2S=G\)
Answer & Solution
Correct Answer
(A) \(S (R+ G) = RG\)
Step-by-step Solution
Detailed explanation
According to Ohm's Law, \(I\) \(=\frac{V}{R}\) \(\mathrm{I}_{\mathrm{g}}=\frac{\mathrm{V}}{\mathrm{R}+\mathrm{G}}\) where, \(I \)\(_{g}\) - Galvanometer current, \(G-\)Galvonometer resistance When shunt of resistance \(S\) is connected parallel to the Galvanometer then…
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