JEE Mains · Physics · STD 12 - 5. Magnetism and matter
A paramagnetic substance in the form of a cube with sides \(1\, cm\) has a magnetic dipole moment of \(20 \times 10^{-6}\, J/T\) when a magnetic intensity of \(60 \times 10^3\, A/m\) is applied. Its magnetic susceptibility is
- A \(3.3 \times {10^{ - 2}}\)
- B \(40.3 \times {10^{ - 2}}\)
- C \(2.3 \times {10^{ - 2}}\)
- D \(3.3 \times {10^{ - 4}}\)
Answer & Solution
Correct Answer
(D) \(3.3 \times {10^{ - 4}}\)
Step-by-step Solution
Detailed explanation
\({\chi=\frac{1}{\mathrm{H}}}\) \({\mathrm{I}=\frac{\text { Magnetic moment }}{\text { Volume }}}\) \({\mathrm{I}=\frac{20 \times 10^{-6}}{10^{-6}}=20\, \mathrm{N} / \mathrm{m}^{2}}\) \({x=\frac{20}{60 \times 10^{3}}=\frac{1}{3} \times 10^{-3}}\)…
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