JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
The mean free path and the average speed of oxygen molecules at 300 K and 1 atm are \(3 \times 10^{-7} \mathrm{~m}\) and \(600 \mathrm{~m} / \mathrm{s}\) respectively. Find the frequency of its collisions.
- A \(2 \times 10^{10} / \mathrm{s}\)
- B \(9 \times 10^5 / \mathrm{s}\)
- C \(2 \times 10^9 / \mathrm{s}\)
- D \(5 \times 10^8 / \mathrm{s}\)
Answer & Solution
Correct Answer
(C) \(2 \times 10^9 / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { Frequency }=\frac{1}{T}=\frac{V_{\text {avg }}}{\lambda} \\ & =\frac{600}{3 \times 157}=2 \times 10^9 \mathrm{sec}^{-1}\end{aligned}\)
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