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JEE Mains · Physics · STD 11 - 10.2 transmission of heat

Read the following statements: \(A.\) When small temperature difference between a liquid and its surrounding is doubled the rate of loss of heat of the liquid becomes twice. \(B.\) Two bodies \(P\) and \(Q\) having equal surface areas are maintained at temperature \(10^{\circ}\,C\) and \(20^{\circ}\,C\). The thermal radiation emitted in a given time by \(P\) and \(Q\) are in the ratio \(1: 1.15\) \(C.\) A carnot Engine working between \(100\,K\) and \(400\,K\) has an efficiency of \(75 \%\) \(D.\) When small temperature difference between a liquid and its surrounding is quadrupled, the rate of loss of heat of the liquid becomes twice. Choose the correct answer from the options given below :

  1. A \(A, B, C \) only
  2. B \(A, B\) only
  3. C \(A, C\) only
  4. D \(B, C, D\) only
Verified Solution

Answer & Solution

Correct Answer

(A) \(A, B, C \) only

Step-by-step Solution

Detailed explanation

Heat Transfer A. by Newton's low of colling \(\frac{d \theta}{d t}=\propto \Delta T\) B. \(H =\frac{d \theta}{d t}=\sigma e AT ^{4} \Rightarrow \frac{ H _{ P }}{ H _{Q}}=\left(\frac{ T _{ P }}{ T _{Q}}\right)^{4}=\left(\frac{283}{293}\right)^{4}\)…
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