JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
A solid sphere and a hollow sphere of the same mass and of same radius are rolled on an inclined plane. Let the time taken to reach the bottom by the solid sphere and the hollow sphere be \(t_1\) and \(t_2\), respectively, then...
- A \(t_1\gt t_2\)
- B \(t_1=t_2\)
- C \(t_1 \lt t_2\)
- D \(t_1=2 t_2\)
Answer & Solution
Correct Answer
(C) \(t_1 \lt t_2\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \mathrm{t}=\sqrt{\frac{2 \ell}{\mathrm{a}_{\mathrm{cm}}}} \\ & \mathrm{a}_{\mathrm{cm}}=\frac{\mathrm{g} \sin \theta}{1+\frac{\mathrm{I}_{\mathrm{cm}}}{\mathrm{MR}^2}} \\ & \mathrm{a}_1=\mathrm{a}_{\mathrm{cm}_1}=\frac{5 \mathrm{~g} \sin \theta}{7} \ldots . .…
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