JEE Mains · Physics · STD 11 - 13. oscillations
The function of time representing a simple harmonic motion with a period of \(\frac{\pi}{\omega}\) is :
- A \(\sin (\omega t)+\cos (\omega t)\)
- B \(\cos (\omega t)+\cos (2 \omega t)+\cos (3 \omega t)\)
- C \(\sin ^{2}(\omega t)\)
- D \(3 \cos \left(\frac{\pi}{4}-2 \omega t\right)\)
Answer & Solution
Correct Answer
(D) \(3 \cos \left(\frac{\pi}{4}-2 \omega t\right)\)
Step-by-step Solution
Detailed explanation
Time period \(T =\frac{2 \pi}{\omega^{\prime}}\) \(\frac{\pi}{\omega}=\frac{2 \pi}{\omega^{\prime}}\) \(\omega^{\prime}=2 \omega \rightarrow\) Angular frequency of \(SHM\) Option \((3):\)…
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