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JEE Mains · Physics · STD 11 - 5. work,energy,power and collision

A body \(A\) of mass \(\mathrm{m}\) is moving in a circular orbit of radius \(\mathrm{R}\) about a planet. Another body \(\mathrm{B}\) of mass \(\frac{\mathrm{m}}{2}\) collides with \(\mathrm{A}\) with a velocity which is half \(\left(\frac{\overrightarrow{\mathrm{v}}}{2}\right)\) the instantaneous velocity \(\overrightarrow{\mathrm{v}}\) of \(\mathrm{A}\) The collision is completely inelastic. Then, the combined body

  1. A starts moving in an elliptical orbit around the planet
  2. B continues to move in a circular orbit
  3. C Falls vertically downwards towards the planet
  4. D Escapes from the Planet's Gravitational field.
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Answer & Solution

Correct Answer

(A) starts moving in an elliptical orbit around the planet

Step-by-step Solution

Detailed explanation

Initially, the body of mass \(\mathrm{m}\) is moving in a circular orbit of radius \(\mathrm{R} .\) So it must be moving with orbital speed. \(\mathrm{v}_{0}=\sqrt{\frac{\mathrm{GM}}{\mathrm{R}}}\) After collision, let the combined mass moves with speed \(v_{1 }\)…
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