JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A wire carrying current \(I\) is bent in the shape \(A\,B\,C\,D\,E\,F\,A\) as shown, where rectangle \(A\,B\,C\,D\,A\) and \(A\,D\,E\,F\,A\) are perpendicular to each other. If the sides of the rectangles are of lengths \(a\) and \(b,\) then the magnitude and direction of magnetic moment of the loop \(A\,B\,C\,D\,E\,F\,A\,\) is
- A \(\sqrt{2}\) \(abI\), along \(\left(\frac{\hat{j}}{\sqrt{2}}+\frac{\hat{ k }}{\sqrt{2}}\right)\)
- B \(\sqrt{2}\) \(abI,\) along \(\left(\frac{\hat{j}}{\sqrt{5}}+\frac{2 \hat{k}}{\sqrt{5}}\right)\)
- C \(abI,\) along \(\left(\frac{\hat{j}}{\sqrt{2}}+\frac{\hat{k}}{\sqrt{2}}\right)\)
- D \(abI,\) along \(\left(\frac{\hat{j}}{\sqrt{5}}+\frac{2 \hat{ k }}{\sqrt{5}}\right)\)
Answer & Solution
Correct Answer
(A) \(\sqrt{2}\) \(abI\), along \(\left(\frac{\hat{j}}{\sqrt{2}}+\frac{\hat{ k }}{\sqrt{2}}\right)\)
Step-by-step Solution
Detailed explanation
Sol. \(\quad M=N I A\) \(N =1\) For \(ABCD\) \(\overrightarrow{ M }_{1}= abI \hat{ K }\) For \(DEFA\) \(\overrightarrow{ M }_{2}= abI \hat{ j }\) \(\overrightarrow{ M }=\overrightarrow{ M }_{1}+\overrightarrow{ M }_{2}\) \(=\operatorname{ab} I (\hat{ k }+\hat{j})\)…
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