JEE Mains · Physics · STD 12 - 3. current electricity
A meter bridge setup is shown in the figure. It is used to determine an unknown resistance \(R\) using a given resistor of \(15\,\Omega\). The galvanometer \((G)\) shows null deflection when tapping key is at \(43\,cm\) mark from end \(A\). If the end correction for end \(A\) is \(2\,cm\). then the determined value of \(R\) will be__________ \(\Omega\)
- A \(19\)
- B \(20\)
- C \(24\)
- D \(18\)
Answer & Solution
Correct Answer
(A) \(19\)
Step-by-step Solution
Detailed explanation
Using the conditions of a balanced wheat stone bridge and adding the end correction. \(\frac{15}{(43+2)}=\frac{R}{(102-45)} \Rightarrow R=\frac{57}{45} \times 15\) \(R=19\,\Omega\)
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