JEE Mains · Maths · STD 11 - 6. permutation and combination
The total number of \(5\)-digit numbers, formed by using the digits \(1,2,3,5,6,7\) without repetition, which are multiple of \(6\), is
- A \(36\)
- B \(48\)
- C \(60\)
- D \(72\)
Answer & Solution
Correct Answer
(D) \(72\)
Step-by-step Solution
Detailed explanation
To make a no. divisible by \(3\) we can use the digits \(1,2,5,6,7\) or \(1,2,3,5,7\) Using \(1,2,5,6,7\), number of even numbers is \(=4 \times 3 \times 2 \times 1 \times 2=48\) Using \(1,2,3,5,7\), number of even numbers is \(=4 \times 3 \times 2 \times 1 \times 1=24\)…
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